bunnyfurlife
contestada

HELP ASAP!!
Given: ABCD is a parallelogram.
Prove: ∠A and ∠D are supplementary.

By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are ? angles. Because AB and DC are ? , the same-side interior angles must be ? by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.

HELP ASAP Given ABCD is a parallelogram Prove A and D are supplementary By the definition of a parallelogram ABDC AD is a transversal between these sides so A a class=

Respuesta :

sorry this is so late but the answers are: same-side interior, parallel, and supplementary

A parallelogram is a quadrilateral with four sides. The opposite sides of the parallelogram are equal and parallel.

In the given figure, AB||DC. AD is the transversal, such that:

∠A + ∠D = 180-degrees.

  • The parallelogram is a quadrilateral with equal and parallel sides, such that the interior angles present on the same side of the transversal are supplementary.

  • The sum of supplementary angles is equal to 180-degrees.

  • From the theorem of same-side interior angles, the supplementary angles present on the parallel lines must be intersected by a transversal.

  • Since, in the parallelogram ABCD, AD is the transversal.

  • From the property of transversal, the interior angles on the same side of the transversal are supplementary.

Therefore, ∠A and ∠D are supplementary and their sum is equivalent to 180-degrees.

To know more about parallelogram and their properties, refer to the following link:

https://brainly.com/question/15584566

Otras preguntas