Answer:
1. option A is correct i.e., [tex]\(90^{\circ}[/tex].
2. option B is correct.
3. the coordinates of the car after a rotation of [tex]\(270^{\circ}[/tex] is (0,-30).
Step-by-step explanation:
1. The angle of rotation is [tex]\(90^{\circ}[/tex].
To calculate the angle of rotation we can use a protractor and measure the angle between two corresponding angles, using point C as a center.
2. Given: ΔPRS with coordinates P(-3,2), R(2,5) and S(0,0) is rotated through an angle of 270°, the new image will be as follows;
The formula for rotation through 270° is: (x,y) → (y,-x)
hence our image will be at point:
P(-3,2)→P'(2,3)
R(2,5)→R'(5,-2)
S(0,0)→S'(0,0)
from the above, the approximate image will be option B.
3. Given: Ferris wheel is drawn on a coordinate plane at the point P(30,0). The coordinates of the car after a rotation of [tex]\(270^{\circ}[/tex] is (0,-30).
Because the formula for rotation through 270° is: (x,y) → (y,-x).
So, point P(30,0)→P'(0,-30).
