A thief steals an ATM card and must randomly guess the correct three​-digit pin code from a 10​-key keypad. Repetition of digits is allowed. What is the probability of a correct guess on the first​ try?

Respuesta :

Since repetition is allowed, there are 10(10)(10) choices available; 10 for the first digit, 10 for the second digit, and 10 for the third digit, coming out to a possible 1000 combinations.  The probability of getting the 1 correct on the first try would be 1/1000.

The probability of a correct guess on the first​ try will be [tex]0.001[/tex] .

What is Probability ?

Probability is the ratio of number of favorable outcome to the

i.e. Probability [tex]P(E)=\frac{number\ of\ favorable\ outcome}{Total\ number\ of\ outcomes.}[/tex]

We have,

An ATM Card having three-digit code.

Repetition of digits is allowed.

So,

As Repetition is allowed, and we have [tex]10-[/tex]key keypad, and have to guess [tex]3[/tex] digit code,

Then

Total number of outcomes [tex]=10*10*10=1000[/tex]

And

Number of favorable outcome [tex]=1[/tex]

So,

Probability [tex]P(E)=\frac{number\ of\ favorable\ outcome}{Total\ number\ of\ outcomes.}[/tex]

[tex]P(E)=\frac{1}{1000}[/tex]

[tex]P(E)=0.001[/tex]

So, the Probability of correct guess is [tex]0.001[/tex] .

Hence, we can say that the probability of a correct guess on the first​ try is [tex]0.001[/tex] .

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