We know that perimeter is equal to 2l+2w or l+l+w+w.
We also know that the length is 6 meters longer than the width.
Based on this we can create the following formula to find the dimensions:
28= (w+6)+(w+6)+w+w
Then to solve, it's just simple algebra.
First, combine like terms: 28= w+w+w+w+6+6 28= 4w+12
The next thing we do is isolate the variable by subtracting 12 from each side: 28-12 = 4w+12-12 16= 4w
The next thing we do is divide both sides by the coefficient (4): 16/4 = 4w/4
And this gives us the answer that w=4.
Now to find the dimensions:
We know that the width is equal to 4.
We also know that the length is equal to 6 more than the width. If the width is 4 then the length is 4+6 or 10.
So there you have it, the dimensions of the room would be 4x10.
