Respuesta :
Let The Wall Street Journal be A, and USA Today be B. We want
P(A∩B^c), or the intersection of A and Not B happening.
P(A∩B^c)=P(A∪B)-P(B) = [P(A)+P(B)-P(A and B)]-P(B)
=(0.45+0.40-0.25)-0.40 = 0.2.
P(A∩B^c), or the intersection of A and Not B happening.
P(A∩B^c)=P(A∪B)-P(B) = [P(A)+P(B)-P(A and B)]-P(B)
=(0.45+0.40-0.25)-0.40 = 0.2.
Answer:
20% = 0.2
Step-by-step explanation:
Let A = Wall Street Journal = 45%
Let B = USA Today = 40%
Let C = Both = 25%
C = A∩B = 25%
The focus is to determine that a random library subscribes to A only
The probability of subscribing to A = 45%
However, there are subscribers to A that are also subsribed to B
This group is C = 25%
To find the probability of subscribing to A only;
Probability of A only = P{A} - P{A∩B} = P{A} - P{C}
P{A} only = 45% - 25% = 20%
P{A} only = 0.2