For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the rate constant at 666 K is 8.28×10-3 /s. The activation energy for the gas phase decomposition of 1-bromopropane is

Question

26-02-2018
Chemistry

contestada

For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the rate constant at 666 K is 8.28×10-3 /s. The activation energy for the gas phase decomposition of 1-bromopropane is

Respuesta :

Otras preguntas

Evaluate the function. f(x) = -22 +19 Find f(3)

what type of correlation does the following have? the amount of money a person earns vs. the last four digits of their social security number

A cat runs up a 45 m tall tree in 1.4 s. What is the average velocity of the cat?0.031 m/s, up44 m/s, up63 m/s, up32 m/s, up

write a letter to your father in abroad telling him some difficulties you've been facing

Take the last paragraph of the novel and discuss it in Christian terms. the book is called TWENTY THOUSAND LEAGUES UNDER THE SEA

At first, why did the other farmers not help Mr. Jones?

Alex spent $126.42 on new school clothes and supplies. If $86.23 of that was spent on supplies, what percent of what she spent on supplies?

pleas help me!!??!!!??!!?!

HELP ME PLEASECamila wants her photo to show the location where it was taken. Where is this information MOST LIKELY to be included? the background the foregroun

an object is acted by force of 22 newtons to the right and a force of 13 newtons to left

Dejanras Dejanras · Answer 1 · 2018-02-26T22:52:25+01:00

Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k₁/k₂) = Ea/R (1/T₂ - 1/T₁).
k₁ = 0,000643 1/s.
k₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁ = 1/622 K = 0,0016 1/K.
1/T₂ = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.