Respuesta :
the equation of the line parallel to 5x+2y=12 and passes through the point (-2, 4) is equal to y= -5/2x - 1
Answer: The required equation of the line is [tex] y=-\dfrac{5}{2}x-1.[/tex]
Step-by-step explanation: We are given to find the equation of the line that is parallel to the following line and passes through the point (-2, 4) :
[tex]5x+2y=12~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We know that
the slope-intercept form of the equation of a straight line is given by
[tex]y=mx+c,[/tex]
where m is the slope of the line.
From equation (i), we have
[tex]5x+2y=12\\\\\Rightarrow 2y=-5x+12\\\\\Rightarrow y=-\dfrac{5}{2}x+6.[/tex]
So, the slope of line (i) is given by
[tex]m=-\dfrac{5}{2}.[/tex]
We know that the slopes of two parallel lines are equal. So, the slope of the new line will be
[tex]m=-\dfrac{5}{2}.[/tex]
Since the line passes through the point (-2, 4), so its equation will be
[tex]y-4=m(x-(-2))\\\\\\\Rightarrow y-4=-\dfrac{5}{2}(x+2)\\\\\\\Rightarrow y-4=-\dfrac{5}{2}x-5+4\\\\\\\Rightarrow y=-\dfrac{5}{2}x-1.[/tex]
Thus, the required equation of the line is [tex] y=-\dfrac{5}{2}x-1.[/tex]
