Respuesta :
the complete question in the attached figure
we know that
m∠BAC = 50°
m∠CBA = 70°
and
m∠BAC+m∠CBA+m∠ACB=180°
then
m∠ACB=180-[m∠BAC+m∠CBA]---------> 180°-[50°+70°]=60°
m∠ACB=60°
remember that
BC║DE
therefore
m∠ACB=m∠DEC
m∠DEC=60°
the answer is m∠DEC=60°
we know that
m∠BAC = 50°
m∠CBA = 70°
and
m∠BAC+m∠CBA+m∠ACB=180°
then
m∠ACB=180-[m∠BAC+m∠CBA]---------> 180°-[50°+70°]=60°
m∠ACB=60°
remember that
BC║DE
therefore
m∠ACB=m∠DEC
m∠DEC=60°
the answer is m∠DEC=60°

Answer:
the m∠DEC=60°
Step-by-step explanation:
As given, information the triangle is shown in figure-1
Given:
m∠BAC = 50°
m∠CBA = 70°
we need to find m∠DEC
Since, sum of interior angles of triangle is 180°.
In triangle ABC,
m∠BAC+m∠CBA+m∠ACB=180°
50° + 70° + m∠ACB =180°
120° + m∠ACB =180°
subtract 120° from both the sides in above,
m∠ACB =180° - 120°
m∠ACB =160°
from the figure, we can see that BC║DE,
therefore
m∠DEC=m∠ACB
m∠DEC=60°
Therefore, the m∠DEC=60°
