Answer: Our factorized term will be
2xy(2x+5)(2x-3)
Explanation:
Since we have given that
[tex]8x^3y-8x^2y-30xy[/tex]
All we need to do is to factorise this expression.
Here are the steps given below:
[tex]2xy(4x^2-4x-15)[/tex]
By manipulating the terms, we get:
[tex]2xy[(2x)^2-4x+1-16]\\\\2xy[(2x-1)^2-16]\\\\2xy[(2x-1)^2-(4)^2]\\\\2xy[(2x-1-4)(2x-1+4)]\\\\2xy[(2x-5)(2x+3)][/tex]
Alternatively,
By using splitting the middle terms,
[tex]2xy(4x^2-4x-15)\\\\2xy(4x^2-10x+6x-15)\\\\2xy[2x(2x-5)+3(2x-5)]\\\\2xy(2x-3)(2x+5)[/tex]
Hence, our factorized term will be
2xy(2x+5)(2x-3)
