2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?


3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?

Respuesta :

We have that the gravitational energy is given by: U=mgh where m is the mass of the object (in kg), g is the gravitational acceleration and h is the height of the object (in meters). Hence, h=U/(m*g) where g=9.8 m/s^2. Thus, h=20 m if we substitute.
Similarly, substituting in b, we have that the height of the model plane is 10 m. The kinetic energy is given by: K=[tex] \frac{1}{2} *m*u^2[/tex] where u is the speed of the object. Hence, solving for u we have u=[tex] \sqrt{2K/m} [/tex]. Substituting, we have that u=5m/s.

As per the first question we have to calculate the height at which the boulder is present.

we have been given the mass of the boulder [m] as 200 kg.

The gravitational potential energy is given as 39,000 Joule.

The gravitational potential energy at a height ' h'  from the surface earth is given as P.E= mass×height×acceleration due to gravity

The value of g=9.8 m/s^2

   Hence height [h][tex]=\frac{P.E}{mg}[/tex]

                              =[tex]\frac{39000}{200*9.8} metre[/tex]

                              =19.8979 metre

As per the second question we have to calculate the sped and height of the model airplane.

the mass of model airplane is 1 kg

The kinetic energy [K.E] of the airplane is 12.5 joule

we have K.E[tex]=\frac{1}{2} mass*speed^2[/tex]

                K.E[tex]=\frac{1}{2}mv^2[/tex]

                 [tex]v^2=\frac{2K.E }{m}[/tex]

                  [tex]v^2=\frac{2*12.5}{1}[/tex]

                    [tex]v=\sqrt{25}[/tex]

                      v=5 m/s

Again we have to calculate the height [h]

The potential energy is given as 98 Joule.

we know that P.E= mgh

                        tex]h=\frac{P.E}{mg}[/tex]  

                       =[tex]\frac{98}{1*9.8} metre[/tex]

                       =10 metre