Step 1-------> set variables. Let x-----------> number of dimes y-----------> number of quarters
Step 2: set the equation and solve for the variable we know that 0.10 x+0.25 y=3.45---------------> 10x+25y=345 equation (1) x=y+10 equation (2) substituting 2 in 1 10[y+10]+25y=345----> 10y+100+25y=345 35y=345-100-----------> y=245/35=7 x=y+10--------> x=7+10=17
Step 3: plug in the value of x and y from last step into the variables.
y=7--------> number of quarters coins x=17-------> number of dimes coins
If we assume the quarters are x, then the dimes are 10+x Thus, 0.25x + 0.1(10+x) = 3.45 = 0.25x +1 +0.1 x = 3.45 = 0.35 x = 3.45 -1 = 0.35x = 2.45 x = 7 Therefore, the quarters are 7, while the dimes were 17, Thus a total of 24 coins
