Ashchu117
contestada

***50 POINTS***
Which of the following combinations will result in a reaction that is only spontaneous at low temperatures?
A) positive enthalpy change and positive entropy change
B) positive enthalpy change and negative entropy change
C) negative enthalpy change and positive entropy change
D) negative enthalpy change and negative entropy change

I think it's C, or maybe D, please help!

Respuesta :

sibadiedaniela

The correct answer is D)negative enthalpy change and negative entropy change

Eduard22sly

Given the data, the correct statement is negative enthalpy change and negative entropy change (Option D)

Gibbs free energy

ΔG = ΔH – TΔS

Where

  • ΔG is the Gibbs free energy
  • ΔH is the enthalpy change
  • T is the temperature
  • ΔS is the change in entropy

NOTE

  • ΔG = +ve (non spontaneous)
  • ΔG = 0 (equilibrium)
  • ΔG = –ve (spontaneous)

Since the reaction is at low temperature, then TΔS must be smaller than ΔH

Thus, ΔH and ΔS must be negative for the reaction to be spontaneous as illustrated below:

  • ΔH = -ve (greater)
  • ΔS = -ve
  • ΔG =?

ΔG = ΔH – TΔS

ΔG = (-ve) – T(-ve)

ΔG = (-ve) – T(-ve)

ΔG = –ve

Learn more about Gibbs free energy:

https://brainly.com/question/9552459

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