Respuesta :
moles oxygen = 0.0338 x 11 =0.372
atoms oxygen = 0.372 x 6.02 x 10^23=2.24 x 10^23
moles water = 7 x 0.0338 =0.237
atoms oxygen = 0.372 x 6.02 x 10^23=2.24 x 10^23
moles water = 7 x 0.0338 =0.237
Answer: The number of oxygen atoms in given amount of magnesium sulfate heptahydrate is [tex]2.265\times 10^{23}[/tex]
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of magnesium sulfate heptahydrate = 8.43 g
Molar mass of magnesium sulfate heptahydrate = 246.47 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of magnesium sulfate heptahydrate}=\frac{8.43g}{246.47g/mol}=0.0342mol[/tex]
The chemical formula of magnesium sulfate heptahydrate is [tex]MgSO_4.7H_2O[/tex]
1 mole of magnesium sulfate heptahydrate contains 1 mole of magnesium atoms, 1 mole of sulfur atoms, 11 moles of oxygen atoms and 14 moles of hydrogen atoms
According to mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of particles
So, 0.0342 moles of magnesium sulfate heptahydrate will contain = [tex](11\times 0.0342\times 6.022\times 10^{23})=2.265\times 10^{23}[/tex] number of oxygen atoms
Hence, the number of oxygen atoms in given amount of magnesium sulfate heptahydrate is [tex]2.265\times 10^{23}[/tex]
