Тhe third angle of the triangle = 90 - 60 = 30°
In a 30-60-90 triangle the side opposite the 30 degree angle is half the length of the hypotenuse, therefore [tex]y = \frac{8 \sqrt{3} }{2}=4 \sqrt{3} [/tex]
[tex]x=8 \sqrt{3} \cdot \cos30^o =8 \sqrt{3} \cdot { \frac{ \sqrt{3} }{2} } =12[/tex]
The answer is x = 12, y = 4√3
