We should bring all of those numbers to the same denominator: here 45 is best, since it's a multiplication of all the denominators present (3,15,5,9).
So the numbers will be:
[tex] 2\frac{30}{45} [/tex], [tex] 2\frac{18}{45} [/tex], [tex] 2\frac{27}{45} [/tex], [tex] 2\frac{20}{45} [/tex]
I calculated this like this:
(on the example of [tex] 2\frac{2}{3} [/tex])
[tex] 2\frac{2}{3}=2\frac{2*15}{3*15} =2\frac{30}{45}[/tex]
I multiphied by 15 because 45/3=13
so now we can order those numbers from the smallest to the largest:
[tex] 2\frac{18}{45} [/tex] [tex] 2\frac{20}{45} [/tex], [tex] 2\frac{27}{45} [/tex], [tex] 2\frac{30}{45} [/tex],
which correspond to
[tex] 2\frac{6}{15} [/tex] [tex] 2\frac{4}{5} [/tex], [tex] 2\frac{3}{5} [/tex], [tex] 2\frac{2}{3} [/tex],
