shaymulti
shaymulti
22-01-2016
Mathematics
contestada
expand y=-2(4x-1)(4x+1)
Respuesta :
Billymkhoi
Billymkhoi
22-01-2016
y= -2(4x -1)(4x+1)
⇒ y= -2[(4x)^2 -1^2] (because (4x)^2 -1^2= (4x-1)(4x+1))
⇒ y= -2(16x^2 -1)
⇒ y= -2*16x^2 -2*(-1) (distributive property)
⇒ y= -32x^2+ 2
The final answer is y= -32x^2+ 2
~
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ayah1
ayah1
22-01-2016
y = -2(4x - 1)(4x + 1)
y = (-2*4x -2*-1)(4x + 1)
y= (-8x + 2)(4x + 1)
y = -8x*4x + -8x*1 + 2*4x + 2*1
y = -32x² + -8x + 8x + 2
y = -32x² + 2
answer
Answer Link
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