Answer:
[tex]6.83.10^{-3} mol FeCl_{3}[/tex]
Explanation:
We have to find the molar mass of the compound.
We must multiply the atomic mass of each element of the compound by the number of atoms of each one
[tex]FeCl_{3}[/tex]
molar mass [tex]FeCl_{3}[/tex]
[tex]Fe= 56g/mol\\Cl= 35g/mol[/tex]
[tex]FeCl_{3}= 56g/mol+3(35g/mol)=161g/mol[/tex]
We know that in 1 mol of [tex]FeCl_{3}[/tex] it has a mass of 161g.
Now we can find out how many moles of [tex]FeCl_{3}[/tex] are in 1.1 g.
[tex]161g FeCl_3\longrightarrow 1 mol FeCl_3\\ 1.1g FeCl_3\longrightarrow x\\ x=\frac{1.1g FeCl_3.1 molFeCl_3}{161 g FeCl_3} = 6.83.10^{-3} mol FeCl_{3}[/tex]
