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Willchemistry
Molar mass of dinitrogen trioxide ( N2O3 ) = 76.01 g/mol
 
1 mole ------------ 76.01 g
 ? ------------------ 75.0 g

Number of moles:

n = m / mm

n = 75.0 / 76.01

n = 0.9867 moles

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Answer: The amount of given number of dinitrogen trioxide is 0.99 moles.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

We are given:

Given mass of dinitrogen trioxide = 75.0 g

Molar mass of dinitrogen trioxide = 76 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of dinitrogen trioxide}=\frac{75.0g}{76g/mol}=0.99mol[/tex]

Hence, the amount of given number of dinitrogen trioxide is 0.99 moles.

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