Respuesta :

qoiop314
you can use this formula
[tex]{x}^{2} + (a + b)x + ab[/tex]
a and b are the solutions to the equation

[tex] {x}^{2} + ( - \frac{2}{5} + \frac{1}{3} )x + ( - \frac{2}{5} \times \frac{1}{3} ) = 0 \\ {x}^{2} - \frac{1}{15}x - \frac{2}{15} = 0[/tex]