There are 168 ways this team can be formed.
There are 8 sons to choose 2 from and 4 daughters to choose 1 from in the first version of this team:
[tex]_8C_2\times _4C_1
\\
\\\frac{8!}{2!6!}\times\frac{4!}{1!3!}=28\times4=112[/tex]
However, there is another way this team can be formed; it can consist of all sons:
[tex]_8C_3\times_4C_0
\\
\\=\frac{8!}{3!5!}\times\frac{4!}{0!4!}=56\times1=56[/tex]
Adding these together, we have 112+56=168.
