Respuesta :
Hey!To solve this problem, we need to set up two equations and use the system of equations to solve.
Let x be the first number.
Let y be the second number.
(x + y) ÷ 2 = 34
x = 3y
Now, we can use substitution to solve.
(3y + y) ÷ 2 = 34
4y ÷ 2 = 34
2y = 34
y = 17
Now, you plug the value of y in the equation to solve for x.
x = 3*17
x = 51
hope this helps!!
Let x be the first number.
Let y be the second number.
(x + y) ÷ 2 = 34
x = 3y
Now, we can use substitution to solve.
(3y + y) ÷ 2 = 34
4y ÷ 2 = 34
2y = 34
y = 17
Now, you plug the value of y in the equation to solve for x.
x = 3*17
x = 51
hope this helps!!
(x + y)/2 = 34 multiply by 2
x + y = 68 (1)
3x = y (2)
Put 3x in for y in equation 1
x + 3x = 68
4x = 68
x = 17
One of the numbers is 17
The other one is 51
x + y = 68 (1)
3x = y (2)
Put 3x in for y in equation 1
x + 3x = 68
4x = 68
x = 17
One of the numbers is 17
The other one is 51