We rewrite the expression:
5x ^ 2 + 2 = -11x
5x ^ 2 + 11x + 2 = 0
We use the resolver:
x = (-b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
Substituting values:
x = (-11 +/- root ((11) ^ 2 - 4 * (5) * (2))) / (2 * (5))
x = (-11 +/- root (81) / (10)
x = (-11 +/- 9) / (10)
The roots are:
x1 = (-11 + 9) / (10) = -2/10 = -1/5
x2 = (-11 - 9) / (10) = -20/10 = -2
The major root is:
x1 = -1/5 = -0.2
Which is between the integers:
-1 and 0
Answer:
the largest root of 5x ^ 2 + 2 = -11x lies between:
-1 and 0
