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A pet store has a total of 60 dogs and cats. There are 10 fewer cats than dogs. Let c represent the number of cats and d represent the number of dogs. The following system of equations represents the situation: d−10=c d+c=60 How many cats and dogs are in the pet store?

Respuesta :

there would be 35 dogs and 25 cats

Total number of dogs and cats in the pet store are 60

So this gives us our first equation:

[tex] c+d=60 [/tex]...............(1)

[tex] c=60 -d [/tex] .................(2)

There are 10 fewer cats than dogs.

So this gives us the second equation:

[tex] d=c+10 [/tex].............(2)

Now let us use substitution method here.

Plugging the value of c from equation (2) in equation (3)

[tex] d=60-d-10 [/tex]

[tex] d=50-d [/tex]

[tex] 2d=50 [/tex]

this gives d=25

plugging this in equation 2 to find c

[tex] 25 = c+10 [/tex]

c=15

Answer : The pet store has 15 cats and 25 dogs.



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