Answer:
Log base 2 of 6 over log base 2 of 3
Step-by-step explanation:
In order to make a change of base of a logarithm, we apply this principle:
[tex]log_{a}b = \frac{log_{c}b}{log_{c}a}[/tex]
Where:
a: current base of the logarithm [in this case a = 3]
b: argument of the logarithm [in this case b = 6]
c: new base of the logarithm [in this case c = 2]
Applying this principle in this exercise, we have:
[tex]log_{3}6 = \frac{log_{2}6}{log_{2}3}[/tex]
This quotient of logarithms can be expressed as:
Log base 2 of 3 over log base 2 of 6
