Answer:
Write out all of the possible gametes from parent 1 (either parent can be parent 1) along the top of the square. ThenWrite out all of the possible gametes from parent 2 on the left side of the square.Then Divide the square into enough boxes to show the number of possible gamete combinations
Identify the genotype and phenotype of each possible offspring represented within the Punnett square. Then calculate the total percentages for each genotype and phenotype combination.
Important things to keep in mind:
Each box within a Punnett square represents an equal likelihood of occurring, so each represents an equal percentage. In the case of a monohybrid cross with four total squares, each box represents 25% (or a one in four chance). This means the probabilities provided for monohybrid crosses should be in multiples of 25: 0%, 25%, 50%, 75%, or 100%.
When more than one box contains the same genotype or phenotype, their percentages can be added together to determine the probability of an offspring having that genotype or phenotype.
Explanation:
I’m sorry I don’t have the full answer. I’m still struggling with this question myself
