you have a bag of 17 marbles. four are blue, six are green, 2 are red and the others are yellow. what us the probability of drawing a blue marble, replacing it, and then drawing a yellow marble?

Respuesta :

with replacing the first drawn marble, you have independent events and the probability of both happening would be the product of probability of each event.

Looks like this:
Probability of drawing a blue first marble  = [tex] \frac{4}{17} [/tex]
After replacing the blue marble, note that we still have 17 total marbles
Probability of drawing a yellow second marble =  [tex] \frac{5}{17} [/tex]

Now:  P(B, then Y) = [tex] \frac{4}{17} ( \frac{5}{17} )[/tex] = [tex] \frac{20}{289} [/tex]

Or about a 7% chance!