Hello!
To calculate the temperature of 5,85 moles of N₂ gas in a 12,0 L steel bottle under 10,00 atm of pressure we need to use the Ideal Gas Law. This law relates the pressure and volume of a gas with its temperature and number of moles. The calculations for this exercise are shown below:
[tex]P*V=n*R*T \\ \\ T= \frac{P*V}{n*R} \\ \\ T= \frac{(10atm)*(12,0L)}{(5,85 moles)(0,082 \frac{ atm*L}{mol*K})}= 250,16 K
[/tex]
Now we convert this temperature to °C
[tex]T( ^\circ C)=T(K)-273,15)=250,16-273,15=-22,99^\circ C [/tex]
So, the temperature of 5,85 moles of N₂ gas in a 12,0 L steel bottle under 10,00 atm of pressure is -22,99 °C
Have a nice day!
