blakelyc
contestada

1. What values of a, b, and c would you use in the quadratic formula for the following equation?
5x^2 + 9x = 4

a. a= -4, b = 9, c = 5
b. a = 5, b = 9, c = -4
c. a = 5, b = -4, c = 9
d. a = 5, b = 9, c = 4 (I think it might be this one)

2. Which expression gives the solutions of -5 + 2x^2 = -6x ?
( see attachment)

3. Which method is the best method for solving the equation 8x^2 - 13x + 3 = 0?
a. square roots
b. factoring
c. graphing
d. quadratic formula

Even if you can only answer one of these please still answer, thank you!

1 What values of a b and c would you use in the quadratic formula for the following equation 5x2 9x 4 a a 4 b 9 c 5 b a 5 b 9 c 4 c a 5 b 4 c 9 d a 5 b 9 c 4 I class=

Respuesta :

Louli
Question (1):
The general formula of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
5x² + 9x = 4
Rearrange the given equation to look the standard one:
5x² + 9x - 4 = 0
Now, compare the coefficients in the given equation with the standard one, you will find that:
a = 5, b = 9 and c = -4

Question (2):
The given expression is:
 -5 + 2x² = -6x 
Rearrange this expression to be in standard form:
2x² + 6x - 5 = 0
This means that:
a = 2
b = 6
c = -5
The roots of the equation can be found using the formula in the attached image.
Substituting in this formula with the given a, b and c, we would find that the correct choice is third one (I have attached the correct choice)

Question (3):
Quadratic formula (the one used in the previous question, also shown in attached images) is the best method to get the solution of any quadratic equation. This is because, putting the equation in standard form, we can simply get the values of a, b and c, substitute in the formula and get the precise solutions of the equation.

Hope this helps :)

Ver imagen Louli
Ver imagen Louli
MrRoyal

Quadratic equations can be solved using any of the following ways

  • Factorization
  • Matrices
  • Completing the square
  • Graphs
  • Quadratic formula

Question (1):

The equation is given as:

[tex]5x^2 + 9x = 4[/tex]

Rewrite the above equation as

[tex]5x^2 + 9x - 4 = 0[/tex]

A quadratic equation is represented as:

[tex]ax\² + bx + c = 0[/tex]

By comparison:

[tex]a = 5[/tex], [tex]b = 9[/tex] and [tex]c = -4[/tex].

Hence, the values of a, b and c are (b) [tex]a = 5[/tex], [tex]b = 9[/tex] and [tex]c = -4[/tex].

Question (2):

The equation is given as:

[tex]-5 + 2x\² = -6x[/tex]

Rewrite the above equation as

[tex]2x\² + 6x - 5 = 0[/tex]

A quadratic equation is represented as:

[tex]ax\² + bx + c = 0[/tex]

Where:

[tex]x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]

So, the expression is:

[tex]x = \frac{-6 \pm \sqrt{6^2 -4(2)(-5)}}{2(2)}[/tex]

Question (3):

The equation is given as:

[tex]8x^2 - 13x + 3 = 0[/tex]

The above equation cannot be factorized.

So, the best method is to use the quadratic formula

Read more about quadratic equations at:

https://brainly.com/question/1214333

Otras preguntas