Answer:
[tex]y=2\sec (2x)[/tex]
Step-by-step explanation:
We are given a graph of trigonometric function.
As per graph it's look like sec x graph.
First we draw sec x graph and then translate it.
In graph we can see [tex]x=\frac{\pi}{4}[/tex] is vertical asymptote.
But in sec x graph vertical asymptote at [tex]x=\frac{\pi}{2}[/tex] .
y-intercept of sec x graph at (0,1)
But in given graph y-intercept (0,2)
[tex]y=\sec x[/tex]
Change in y-intercept
[tex]y=2\sec x[/tex]
Change in vertical asymptote
[tex]y=2\sec(2x)[/tex]
Thus, Required equation of given graph would be [tex]y=2\sec(2x)[/tex]
