Solve the system of equations 5x-4y=-10 y=2x-5

5x - 4y = -10
y = 2x - 5

You can use substitution method.

5x - 4(2x - 5) = -10
5x - 8x + 20 = -10
-3x = -30
x = 10

y=2x-5
y= 2(10)-5
y=20 - 5
y = 15

So the answer is
( 10 , 15)

Answer Link

XfaiiwashereX XfaiiwashereX · Answer 2 · 2020-06-19T03:38:39+02:00

Answer:

x:10

y:15

Step-by-step explanation:

khan academy

We are given that y=2x−5. Let's substitute this expression into the first equation and solve for x as follows:

[tex]\begin{aligned} 5x-4\pink{y}&=-10\\\\ 5x-4\cdot(\pink{2x-5})&=-10\\\\ 5x-8x+20& = -10\\\\ -3x&=-30\\\\ x&=10 \end{aligned}[/tex]

Since we now know that x=10 we can substitute this value into the second equation to solve for y as follows:

[tex]\begin{aligned} y &= 2\cdot \blue{x}-5 \\\\ y&=2\cdot\blue{10}-5\\\\ y&=15 \end{aligned} y[/tex]

This is the solution to the system:

[tex]\begin{aligned} &x = 10 \\\\ &y=15 \end{aligned}[/tex]

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