The force F exerted by an electric field of magnitude E on a charge q is given by
[tex]F=qE[/tex]
The charge in our problem is [tex]q= 0.0001094 c=1.094\cdot 10^{4} C[/tex] while the force is F=0.182 N, so we can find the magnitude of the electric field by re-arranging the previous formula:
[tex]E= \frac{F}{q}= \frac{0.182 N}{1.094 \cdot 10^{-4} C}=1663.3 N/C [/tex]
