Respuesta :

The prime factorization of 8 is 2³
and ∛8 = [tex] 8^{ \frac{1}{3} } [/tex]

So if you make the replacements

[tex](2 ^{3})^ \frac{1}{3} [/tex] using exponent laws you would multiply the powers resulting in [tex]2^{1} [/tex] = 2 because 3 × 1/3 = 1
If you use the prime factorization method to solve for 8, you will find that you get three multiples of 8, which are 2,2 and 2. Since the root is a (power 3), you have to group three same numbers together into one and it wil be out of root.
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