Respuesta :
check the picture below.
[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh\qquad \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ ------\\ B=\stackrel{14\times 14}{196}\\ h=24 \end{cases}\implies V=\cfrac{1}{3}(196)(24)[/tex]
[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh\qquad \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ ------\\ B=\stackrel{14\times 14}{196}\\ h=24 \end{cases}\implies V=\cfrac{1}{3}(196)(24)[/tex]
