Two ramps are placed back to back as shown. What is the length of the ramp labeled x?

Answer:
Step-by-step explanation:
From the given figure, let ABC and ACD be the two ramps placed back to back.
Then, from ΔABC, we have
[tex]\frac{AC}{AB}=sin13^[\circ}[/tex]
[tex]\frac{y}{9}=sin13^{\circ}[/tex]
[tex]\frac{y}{9}=0.224[/tex]
[tex]y=9{\times}0.224[/tex]
[tex]y=2.02 ft[/tex]
Now, from ΔACD, we have
[tex]\frac{AC}{AD}=sin7^{\circ}[/tex]
[tex]\frac{y}{x}=0.121[/tex]
[tex]x=\frac{2.02}{0.121}[/tex]
[tex]x=16.7 feet[/tex]
Thus, the value of x is 16.7 feet.