contestada

Joy is preparing 15 liters of a 20% saline solution. She only has 30% and 10% solution in her lab. How many liters of the 30% and how many liters of the 10% should she mix to make the 20% solution?

Respuesta :

TimeLord21
If you mix 1 liter of the 10% solution with 1 liter of the 30% solution, you will have 2 liters of 20% solution. Keeping that in mind, you must mix half of the number of liters with 10%, and the other half with 30% in order to get 20%. So knowing all those things, we can do the problem. She needs 15 liters of 20%, so you need to mix 7.5 liters of 10% with 7.5 liters of 30%. After mixing those, you'll have 15 liters of 20% solution. I hope this helps. Please put as brainliest.
varshamittal029

Joy needed 7.5 liters of each of 30% and 10% saline solution in order to make 15 litre 20% saline solution.

What is the Percentage?

The percentage is a measurement of ratio or mathematical quantity or fraction out of total 100.

Let the quantity required for 30% solution be x.

Total quantity of solution is 15 liters

Hence quantity required for 10% solution is = 15-x

Saline in 15 litre of 20% saline solution is = 15*(20/100) = 3

Saline in x litre of 30% saline solution is = x*(30/100) = 0.3x

Saline in (15-x) litre of 10% saline solution is = (15-x)*(10/100) = 0.1(15-x)=1.5-0.1x

According to conditon,

0.3x+(1.5-0.1x) = 3

0.3x-0.1x = 3-1.5

0.2x = 1.5

x = 1.5/0.2 =7.5

Then 30% solution needed 7.5 liters and 10% solution needed (15-7.5)=7.5 liters.

Learn more about Percentage here -

https://brainly.com/question/24304697

#SPJ2

Otras preguntas