Answer is: 6.97 grams grams of hydrogen.
m(CH₄OH) = 46 g; mass of compound.
M(CH₄OH) = Ar(C) + 5·Ar(H) + Ar(O) · g/mol.
M(CH₄OH) = 12 + 5 · 1 + 16 · g/mol.
M(CH₄OH) = 33 g/mol; molar mass.
n(CH₄OH) = m(CH₄OH) ÷ M(CH₄OH).
n(CH₄OH) = 46 g ÷ 33 g/mol.
n(CH₄OH) = 1.4 mol.
In one molecule of CH₄OH, there are five atoms of hydrogen:
n(CH₄OH) : n(H) = 1 : 5.
n(H) = 5 · 1.4 mo.
n(H) = 6.97 mol.
m(H) = n(H) · M(H).
m(H) = 6.97 mol · 1 g/mol.
n(H) = 6.97 g.
