A) The derivative of the function is
.. y' = e^(0.2x)
so the gradients are
.. at x=-2, e^-0.4 ≈ 0.67
.. at x=1, e^0.2 ≈ 1.22
It is difficult to get a good estimate of the gradient by drawing a tangent line. (If you want to try, the second picture is the same graph with the tangent lines turned off. You can print it out and draw your tangent line--or use your favorite picture markup program.)
B) They will likely be within "experimental error", accurate to within a couple of degrees of rotation. (Higher slopes are more difficult to approximate accurately.)
