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Consider the system of equations.

y = –2x + 4,

3y + x = –3

Which statement is true of this system of equations?
A. Both equations are in slope-intercept form.
B. The first equation converted to slope-intercept form is y + 2x = 4.
C. The second equation converted to slope-intercept form is y=-1/3x-1
D. Neither equation is in slope-intercept form.

Respuesta :

iGreen
Slope-intercept form is:

[tex]\sf y=mx+b[/tex]

Where 'm' is the slope and 'b' is the y-intercept.

Only the first equation is in slope-intercept form, so that crosses out the first and last options. It also crosses out the second option since the first equation is already in slope-intercept form.

For the third option, let's convert the second equation into slope-intercept and see for ourselves:

[tex]\sf 3y+x=-3[/tex]

Subtract 'x' to both sides:

[tex]\sf 3y=-x-3[/tex]

Divide 3 to both sides:

[tex]\sf y=-\dfrac{1}{3}x-1[/tex]

So option C is correct.

The true statement regarding the two given equations is required.

Only option C.  The second equation converted to slope-intercept form is [tex]y=-\dfrac{1}{3}x-1[/tex] is correct.

The equations are

[tex]y=-2x+4[/tex]

[tex]3y+x=-3[/tex]

The slope intercept form of a line is given by

[tex]y=mx+c[/tex]

where,

m = Slope

c = y intercept

Comparing the two equations with the slope intercept form we can see that only the first equation is in slope intercept form.

Converting the second equation to slope intercept

[tex]3y+x=-3\\\Rightarrow 3y=-3-x\\\Rightarrow y=\dfrac{-3-x}{3}\\\Rightarrow y=-\dfrac{1}{3}x-1[/tex]

So, only option C.  The second equation converted to slope-intercept form is y=-1/3x-1 is correct.

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