One of the angles of a parallelogram is 36° greater then another one. Find the angles of the parallelogram.

Respuesta :

x + x + 36 + x + x + 36 = 360
4x + 72 = 360
4x = 288
x = 72

so the angles would be

72° , 108°, 72° , 108°.
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Adjacent angles in a parallelogram are complementary angles

The angles in the parallelogram are 27 and 63 degrees

Let the angles be x and y.

Such that:

y = x + 36

Complementary angles add up to 90.

So, we have:

x + y = 90

Substitute x + 36 for y

x + x + 36 = 90

This gives

2x + 36 = 90

Subtract 36 from both sides

2x = 54

Divide through by 2

x = 27

Recall that:

y = x + 36

So, we have:

y = 27 + 36

y = 63

Hence, the angles in the parallelogram are 27 and 63 degrees

Read more about parallelograms at:

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