Respuesta :
[tex]\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad
\begin{cases}
s=length~of\\
\qquad a~side\\
-------\\
s=6
\end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=\cfrac{36\sqrt{3}}{4}
\\\\\\
A=9\sqrt{3}[/tex]