We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:
[tex]L=10logR \\ logR= \frac{L}{10} \\ applying formula \\log_{a}b=c =\ \textgreater \ b= a^{c}\\R= 10^{\frac{L}{10}} [/tex]
For air-raid siren we have:
[tex]R_{1}= 10^{\frac{150}{10}} =10^{15}[/tex]
For jet engine noise we have:
[tex]R_{2}= 10^{\frac{120}{10}} =10^{12}[/tex]
To find out many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
