Hi there!
24. 6x² + 19x + 3
1 3 multiply 6 × 3 = 18
6 1 multiply 1 × 1 = 1
18 + 1 = 19
(x + 3)(6x + 1)
I just simply found the two factors of 6 and 3 that can add up to 19.
This way is useful when the a and c don't have much factors.
27. 5y² + 13y + 6
1 2 5 × 2 = 10
5 3 1 × 3 = 3
10 + 3 = 13
(x + 2)(5x + 3)
30. 16x² + 16x + 3
For this one, 16 has a lot of factors. So you can try "Grouping" method.
You multiply 16 and 3. 16 × 3 =48
Find the factors of 48 that can add up to 16.
Hmm.. 12 and 4 would be great.
Then rewrite the equation.
16x² + 12x + 4x + 3
We would factor 16x² + 12x and 4x + 3 separately.
16x² + 12x 4x + 3 can't be factored more.
4x(4x + 3) 1(4x + 3)
(4x + 1)(4x + 3)
So your answers are....
24. (x + 3)(6x + 1)
27. (x + 2)(5x + 3)
30. (4x + 1)(4x + 3)
Hope this helped!!
