Jordan keeps track of rainy days for one year. This year he counted 27 weeks with at least 1 rainy day. How many weeks had no rainy days?

Respuesta :

There are 52 weeks in a year, so subtract 27 from 52.

52-27=25

There were 25 weeks with no rainy days

The sum of the number of weeks with at least one rainy day and the number of weeks that had no rainy days is equal to 52 weeks. Then the number of weeks that had no rainy days is 25.

What is the linear system?

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

Jordan keeps track of rainy days for one year.

This year he counted 27 weeks with at least 1 rainy day.

Let the number of weeks had no rainy days be x.

We know that in a year, there are 52 weeks.

And we know that the sum of the number of weeks with at least one rainy day and the number of weeks that had no rainy days is equal to 52 weeks.

Then we have

x + 27 = 52

       x = 52 – 27

       x = 25

More about the linear system link is given below.

https://brainly.com/question/20379472