7 years ago, Samir was 3 times as old as Deepak. In 4 years, Samir will be twice as old as Deepak. What is Deepak’s present age?

Respuesta :

3D+11=2D+22
D+11=22
D=11

D= Deepaks age 7 years ago so

11+7=18,his age now
7 years ago:
Let Deepak be x.
Deepak = x
Samir = 3x

Now (7 years later):
Deepak = x + 7
Samir = 3x + 7

In 4 years time:
Deepak = x + 7 + 4 = x + 11
Samir = 3x + 7 + 4 = 3x + 11

Samir is twice as old as Deepak:
⇒ 2(x  + 11) = 3x + 11

Solve x:
2(x  + 11) = 3x + 11
2x + 22 = 3x + 11
3x - 2x = 22 - 11
x = 11

*Remember the x that we define was Deepak's age 7 years ago. 

Find Present Age:
Deepak = x + 7 = 11 + 7 = 18
Samir = 3x + 7 = 3(11) + 7 = 40

Answer: Deepak is 18 years old.