Respuesta :

Yes. It is I = delta q / t

If you think about it, current’s definition is the flow of charge.

This equation then means that current is the rate at which charge flows (coulombs per second).

Answer:

[tex]I=\frac{\Delta q}{\Delta t}[/tex]

Explanation:

The equation that relates charge, time and current is the following:

[tex]I=\frac{\Delta q}{\Delta t}[/tex]

where

I is the current intensity, measured in Amperes (A)

[tex]\Delta q[/tex] is the amount of charge that passes through a given point in a certain interval of time [tex]\Delta t[/tex]. [tex]\Delta q[/tex] is the measured in Coulombs (C) while [tex]\Delta t[/tex] in seconds (s), so the Ampere is defined as

[tex]1 A = \frac{1 C}{1 s}[/tex]

Looking at the equation, we see that the current intensity represents the "rate of flow of charge through a given point".