Answer: [tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]
Explanation: The given equation is:
[tex]NH_3+O_2\rightarrow NO+H_2O[/tex]
Let's balance all the atoms one by one:
Both sides have equal number of N atoms so let's move to the next atom that is H.
There are three H on left side and two H atoms on right side. To balance H, we need to multiply left side by 2 and right side by 3. On doing this, the equation would look as:
[tex]2NH_3+O_2\rightarrow NO+3H_2O[/tex]
Now, left side has two N where as right side has only one N. So, to balance this for N, we need to multiply right side(NO) by 2.
[tex]2NH_3+O_2\rightarrow 2NO+3H_2O[/tex]
Above equation has two oxygen on left side and five oxygen on right side. To make this balance we need to multiply left side oxygen by 2.5.
[tex]2NH_3+2.5O_2\rightarrow 2NO+3H_2O[/tex]
Since whole numbers are used as coefficients for balancing equations, let's multiply the whole equation by 2.
[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]
So, the finally balanced equation is [tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex] .
