Respuesta :
The concentration as % by mass is calculated as below
mass of solute/mass of solvent x100
mass of solute(sugar) = 4g
mass of solvent(water) =46 g
= 4g/ 46 g x100 = 8.7%
mass of solute/mass of solvent x100
mass of solute(sugar) = 4g
mass of solvent(water) =46 g
= 4g/ 46 g x100 = 8.7%
Answer:
[tex]\% m=8.0\%[/tex]
Explanation:
Hello,
In this case, the percent by mass is computed as:
[tex]\% m=\frac{m_{solute}}{m_{solution}}* 100\%=\frac{m_{solute}}{m_{solute}+m_{solvent}}* 100\%[/tex]
In this case, as sugar is the solute and water the solvent, the required percen by mass is:
[tex]\% m=\frac{4g}{4g+46g}* 100\%\\\\\% m=8.0\%[/tex]
Best regards.