The wavelength of the waves on which the radio station will be 254.2 m.The relation of the wavelength, speed, and frequency is applied in the problem.
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The given data in the problem is;
f₁ is the frequency of the cell phone = 1.9 GHz=1.9 ×10⁹ Hz
f₂ is the frequency of the wave =1180 Khz=1.18 ×10⁶ Hz
The wavelength of the cell phone is found as;
[tex]\lambda = \frac{v}{f_1} \\\\ \lambda = \frac{3 \times 10^8}{1.9 \times 10^9} \\\\ \lambda = 0.1578 \ m[/tex]
The wavelength of the radio wave is found as;
[tex]\lambda = \frac{v}{f_2} \\\\ \lambda = \frac{3 \times 10^8}{1.18 \times 10^9} \\\\ \lambda = 254.2 \ m[/tex]
Hence the wavelength of the waves on which the radio station will be 254.2 m
To learn more about the wavelength refer to the link;
brainly.com/question/7143261
