Equation is as follow,
CaCN₂ + 3 H₂O → CaCO₂ + 2 NH₃
According to this equation,
When,
100 g CaCO₃ (1 mole) is produced when = 34 g NH₃ (2 moles) is produced
So,
187 g CaCO₃ will be produced then = X g of NH₃ will produce
Solving for X,
X = (187 g × 34 g) ÷ 100 g
X = 63.58 g of NH₃ will be produced
Result:
Option-2 is correct answer.