Respuesta :
pH+pOH=14
pOH=14-pH=14-3=11
pOH=-log[OH⁻]
11=-log[OH⁻]
[OH⁻]= 10⁻¹¹ =1*10⁻¹¹
Answer is D.
pOH=14-pH=14-3=11
pOH=-log[OH⁻]
11=-log[OH⁻]
[OH⁻]= 10⁻¹¹ =1*10⁻¹¹
Answer is D.
pH scale is used to determine the acidity of a solution
pH is calculated using the H⁺ concentration
pOH scale is used to determine how basic a solution is
pOH is calculated using the OH⁻ concentration
pH and pOH are related in the following formula
pH + pOH = 14
pH = 3
pOH = 14 - 3
pOH = 11
pOH is calculated using the following formula
pOH = - log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = antilog(-11)
[OH⁻] = 1 x 10⁻¹¹ M
the [OH⁻] concentration of lemon juince is D) 1 x 10⁻¹¹ M
